Dear Reader,
Below are four series problems, you have to find the odd one from the given series of numbers.
Question 1
42, 44, 48, 54, 62, 73
a) 73 b) 62 c) 54 d) 42
Answer : a) 73.
Solution :
Each of given numbers except 73 is 1 more than prime numbers.
And the general pattern is P+1; where P = 41, 43, 47, 53, 61, 71
That is, the numbers are obtained as follows:
41 + 1 = 42
43 + 1 = 44
47 + 1 = 48
53 + 1 = 54
61 + 1 = 62
And, 71 + 1 = 72
Hence, the odd one is 73.
Question 2
50, 66, 84, 104, 128, 150
a) 66 b) 128 c) 150 d) 84
Answer : b) 128
Solution :
The pattern to obtain the given numbers are 72 + 1, 82+ 2, 92 + 3, 102 + 4, 112 + 5, 122 + 6.
That is,
72 + 1 = 49 + 1 = 50
82 + 2 = 64 + 2 = 66
92 + 3 = 81 + 3 = 84
102 + 4 = 100 + 4 = 104
112 + 5 = 121 + 5 = 126
122 + 6 = 144 + 6 = 150
Hence, the odd one is 128
Question 3
61, 78, 97, 118, 142, 166
a) 118 b) 142 c) 166 d)78
Answer : b) 142
Solution :
The general pattern is x2 - 3; where x = 8, 9, 10, 11, 12, 13.
The given numbers are obtained as follows:
82 - 3 = 64 - 3 = 61
92 - 3 = 81 - 3 = 78
102 - 3 = 100 - 3 = 97
112 - 3 = 121 - 3 = 118
122 - 3 = 144 - 3 = 141
132 - 3 = 169 - 3 = 166.
Hence, the required odd one is 142.
Question 4
630, 521, 432, 414, 351, 270
a) 630 b) 270 c) 414 d) 521
Answer : d) 521.
Solution :
Sum of the digits in each number is 9 except 521.
That is,
630 = 6 + 3 + 0 = 9
521 = 5 + 2 + 1 = 8
432 = 4 + 3 + 2 = 9
414 = 4 + 1 + 4 = 9
351 = 3 + 5 + 1 = 9
270 = 2 + 7 + 0 = 9
Hence, the required odd one is 521.
Below are four series problems, you have to find the odd one from the given series of numbers.
Question 1
42, 44, 48, 54, 62, 73
a) 73 b) 62 c) 54 d) 42
Answer : a) 73.
Solution :
Each of given numbers except 73 is 1 more than prime numbers.
And the general pattern is P+1; where P = 41, 43, 47, 53, 61, 71
That is, the numbers are obtained as follows:
41 + 1 = 42
43 + 1 = 44
47 + 1 = 48
53 + 1 = 54
61 + 1 = 62
And, 71 + 1 = 72
Hence, the odd one is 73.
Question 2
50, 66, 84, 104, 128, 150
a) 66 b) 128 c) 150 d) 84
Answer : b) 128
Solution :
The pattern to obtain the given numbers are 72 + 1, 82+ 2, 92 + 3, 102 + 4, 112 + 5, 122 + 6.
That is,
72 + 1 = 49 + 1 = 50
82 + 2 = 64 + 2 = 66
92 + 3 = 81 + 3 = 84
102 + 4 = 100 + 4 = 104
112 + 5 = 121 + 5 = 126
122 + 6 = 144 + 6 = 150
Hence, the odd one is 128
Question 3
61, 78, 97, 118, 142, 166
a) 118 b) 142 c) 166 d)78
Answer : b) 142
Solution :
The general pattern is x2 - 3; where x = 8, 9, 10, 11, 12, 13.
The given numbers are obtained as follows:
82 - 3 = 64 - 3 = 61
92 - 3 = 81 - 3 = 78
102 - 3 = 100 - 3 = 97
112 - 3 = 121 - 3 = 118
122 - 3 = 144 - 3 = 141
132 - 3 = 169 - 3 = 166.
Hence, the required odd one is 142.
Question 4
630, 521, 432, 414, 351, 270
a) 630 b) 270 c) 414 d) 521
Answer : d) 521.
Solution :
Sum of the digits in each number is 9 except 521.
That is,
630 = 6 + 3 + 0 = 9
521 = 5 + 2 + 1 = 8
432 = 4 + 3 + 2 = 9
414 = 4 + 1 + 4 = 9
351 = 3 + 5 + 1 = 9
270 = 2 + 7 + 0 = 9
Hence, the required odd one is 521.
