DearReader,
Below are given reasoning questions which you can expect in sbi and other bank po exams.
Question 1
Ram, Suresh, Anil, Krish, Sham and Veer are sitting around a round table facing the center. Ram and Anil are sitting opposite to each other. Krish is not the immediate neighbour of Veer. Suresh is sitting second right of Anil. Sham is between Krish and Ram.
i) Who is sitting opposite to Sham ?
a) Suresh b) Veer c) Anil d) Krish
Answer : b) Veer
Reason :
Based on the information given the following diagram is drawn.
From the above diagram, we can conclude that Veer is sitting opposite to Sham.
ii) Who is sitting between Veer and Ram ?
a) Sham b) Krish c) Suresh d) Anil
Answer : c) Suresh
iii) Who is sitting to the second left of Krish ?
a) Veer b) Sham c) Ram d) Anil
Answer : a) Veer
Question 2
Below question contains a group of digits followed by 4 combination of letters and symbols.Digits are to be coded as per the conditions given below. You have to find out which of the four combination correctly represents the group of digits.
Digit : 2648710395
Symbol code : R # C J * & K T @ S
Conditions :
a) If the first digit is odd and the last digit is even both are to be coded as the code for the first digit.
b) If the first as well as the last digit is odd then both should be replaced by $.
c) If the first digit is even and the last digit is odd then both are to be coded as the code for the last digit.
d) If the first as well as the last digit are even then codes of both are to be interchanged .
i) 265798
a) J#S*@R b) J$S#&R c) CJ*R&K d) None of these
Answer : a) J#S*@R
Reason :
In the question, the first and last digit are even numbers.
If the first and last digit are even numbers then their code should be interchanged. The code for 2 is R and 8 is J.
The remaining number will have their code same. 6 - #, 5 - S, 7 - *, 9 - @
We have to interchange the first and last i.e., R and J should be interchanged.
Now the code is J#S*@R.
ii) 130674
a) C&SK#T b) C*J@KC c) &TK#*& d) None of these
Answer : c) &TK#*&
Reason :
Here the first digit is odd and the last digit is even.
The condition to be followed is, both the first and last digit should be coded with the code of the first digit.
i.e., 1 - & and 4 - C
Based on the condition both should be coded with & and the remaining digit with their code.
The code for the digit is &TK#*&
iii) 580743
a) R&J#TS b) $JK*C$ c) *JK&C* d) None of these
Answer : b) $JK*C$
Reason :
If both the first and last digits are odd then both the digit should be replaced by $ and the remaining digit will have their code.
The code for the digit 580743 is $JK*C$.
iv) 619823
a) T&@JRT b) #&@JRT c) #&@JR# d) None of these
Answer : a) T&@JRT
Reason :
If the first digit is even and the last digit is odd then both the digit should be coded with the last digit.
Code for 6 - # and 3 - T and for the remaining will have same code
Now the code for 619823 is T&@JRT
Below are given reasoning questions which you can expect in sbi and other bank po exams.
Question 1
Ram, Suresh, Anil, Krish, Sham and Veer are sitting around a round table facing the center. Ram and Anil are sitting opposite to each other. Krish is not the immediate neighbour of Veer. Suresh is sitting second right of Anil. Sham is between Krish and Ram.
i) Who is sitting opposite to Sham ?
a) Suresh b) Veer c) Anil d) Krish
Answer : b) Veer
Reason :
Based on the information given the following diagram is drawn.
From the above diagram, we can conclude that Veer is sitting opposite to Sham.
ii) Who is sitting between Veer and Ram ?
a) Sham b) Krish c) Suresh d) Anil
Answer : c) Suresh
iii) Who is sitting to the second left of Krish ?
a) Veer b) Sham c) Ram d) Anil
Answer : a) Veer
Question 2
Below question contains a group of digits followed by 4 combination of letters and symbols.Digits are to be coded as per the conditions given below. You have to find out which of the four combination correctly represents the group of digits.
Digit : 2648710395
Symbol code : R # C J * & K T @ S
Conditions :
a) If the first digit is odd and the last digit is even both are to be coded as the code for the first digit.
b) If the first as well as the last digit is odd then both should be replaced by $.
c) If the first digit is even and the last digit is odd then both are to be coded as the code for the last digit.
d) If the first as well as the last digit are even then codes of both are to be interchanged .
i) 265798
a) J#S*@R b) J$S#&R c) CJ*R&K d) None of these
Answer : a) J#S*@R
Reason :
In the question, the first and last digit are even numbers.
If the first and last digit are even numbers then their code should be interchanged. The code for 2 is R and 8 is J.
The remaining number will have their code same. 6 - #, 5 - S, 7 - *, 9 - @
We have to interchange the first and last i.e., R and J should be interchanged.
Now the code is J#S*@R.
ii) 130674
a) C&SK#T b) C*J@KC c) &TK#*& d) None of these
Answer : c) &TK#*&
Reason :
Here the first digit is odd and the last digit is even.
The condition to be followed is, both the first and last digit should be coded with the code of the first digit.
i.e., 1 - & and 4 - C
Based on the condition both should be coded with & and the remaining digit with their code.
The code for the digit is &TK#*&
iii) 580743
a) R&J#TS b) $JK*C$ c) *JK&C* d) None of these
Answer : b) $JK*C$
Reason :
If both the first and last digits are odd then both the digit should be replaced by $ and the remaining digit will have their code.
The code for the digit 580743 is $JK*C$.
iv) 619823
a) T&@JRT b) #&@JRT c) #&@JR# d) None of these
Answer : a) T&@JRT
Reason :
If the first digit is even and the last digit is odd then both the digit should be coded with the last digit.
Code for 6 - # and 3 - T and for the remaining will have same code
Now the code for 619823 is T&@JRT
